150:a

From: Factitious (x40_at_pacbell.net)
Date: Wed Feb 06 2002 - 17:01:15 PST


>>>>>>
    The statement "fc + rc = (f+r)c unless c is a fantasy number" is
false when f = j, r = 1, and c = 0.  (Note that 0 is a real number and
thus not a fantasy number.)  To show this, I will use my favorite type
of proof, Reductio Ad Absurdum.  In other words, I will show that the
statement reduces to a trivial contradiction, thus demonstrating it to
be false.

(j+1)*0 = j*0+1*0           (statement under consideration)
(j+1)*0 = 1+1*0              (definition of j)
(j+1)*0 = 1+0                  (0 times a real number equals 0)
(j+1)*0 = 1                      (0 plus a real number equals that
number)
j+1 = 1/0                          (divide both sides by 0)
j+1 = j                              (definition of j)
1 = 0                                (subtract j from both sides)

    1 is, of course, not equal to 0.  This system of math may be
fantastic, but it should not be absurd.
    Since a counterexample exists, "fc + rc = (f+r)c unless c is a
fantasy number" is false.

QED.

    I like Reductio Ad Absurdum proofs so much that from now on, all
valid odd-numbered rules must contain a proof of that type.

    To clarify, all integers must indeed be written out using the 10
hendigits.

>>>>>>

Note:
    I don't like reposts much, so I decided to add at least a sentence
of new contribution.  The term "hendigit" is by analogy with
"hendecagon".  Admittedly this is somewhat different from the process by
which "digit" was coined, but I don't know of a Latin word for a person
with an extra finger.  "Polydactyl" might fit that, but it's Greek, so
should not be casually mixed with Latin terminology.

--
Rule Date: 2002-02-07 01:00:09 GMT


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