It was a strange round. 5 players voted too start a new round,
yet only 2 of them did play, plus Garth who came in at the end.
(Come to think of it though, 3 players do equal 4 players and one
more would have been serious trouble because then we would have
been 5 which cannot equal 3+1... It was all for the best probably).

The round was also very short, and I ended up invalidating the
rules I liked best.

Final standings:

Winner: Oerjan		Score: -1
Wizard: Garth		Score:  2
        Ronald		Score: -1
        Everyone else   Score:  0

(Lookahere! Zero mean scoring!)

The new judge is Oerjan (who has promised to be a style point Meanie,
too - haw haw haw [evil grin]).

ROUND 15 - FINAL RULES SET

FANTASY RULE 15:1 (Oerjan)

Every fantasy rule must contain a mathematical puzzle.
Every fantasy rule must answer the puzzle in the previous
rule, if any.
Now, what is two plus two?

   VERDICT: Rule 15:1 is judged VALID

   SCORE: -2

FANTASY RULE 15:2 (Ronald)

**************
*Two plus two*
*equals four!*
*All   Rules,*
*that  have a*
*number  that*
*is a  prime,*
*(like  mine)*
*shall   have*
*the shape of*
*a square. Is*
*67 a  prime,*
*I ask y'all?*
**************

   VERDICT: Rule 15:2 is judged VALID

   SCORE: -2

FANTASY RULE 15:3 (Oerjan)

        67 is no prime. Because
     when you multiply 6 by 9, you
  get 42, as documented in The Hitch-
hiker Series. Adding 9, we get 7*9 = 51.
Dividing by 3, we get 7*3 = 17, and then
  subtracting 7 gives us 7*2 = 10. Now
7*13 = 7*(3+2*5) = 17 + 10*5 = 67, Q.E.D.
I shall leave it to my successor to show
  why 3 is not a prime number, either.
  To increase the mathematical standard
   of our rules, each future rule must
      contain a proof or a diagram,
               like this:

      7 ---\             *
            }-> (7,13) ----> 67
      13 --/


    VERDICT: Rule 15:3 is judged VALID

    SCORE: 1


KUNNE's COROLLARY:
  Oerjan's Last Theorem (that 3 is not prime) has interesting
  consequences.
  3 is not prime, so there must be an integer other than 1 and 3, that
  divides 3. This can only be 2. Hence 2*2=3 or 4=3.

  In Fantasy Rule terms this can only mean that Rule 15:4
  is identical to 15:3!


FANTASY RULE 15:5 (Ronald)

***************************
*"prime"  :   first  rate,*
*             fundamental.*
*"odd"    :   irregular,  *
*                 unusual.*
*                         *
*Everybody knows that 3 is*
*"odd".  But an odd,  that*
*is, an  irregular and un-*
*usual  number  can not be*
*fundamental  and first as*
*well.                    *
*Hence:  3 is  not  prime.*
*The puzzle:              *
*find the number that goes*
*in the last corner.      *
*                         *
*     5  ---  8 --- 21    *
*     |       |      |    *
*     |       |      |    *
*     |       |      |    *
*     7  ---  4 --- 15    *
*     |       |      |    *
*     |       |      |    *
*     |       |      |    *
*    19  --- 16 --- ??    *
***************************

    VERDICT: Rule 15:5 is judged VALID

    SCORE: 0

FANTASY RULE 15:i (Garth)

The missing number of the square is 1.
This rule shall be numbered 15:i, where i is the
square root of -1.
Rule 15:3 proves that 3 is not a prime.  Therefore,
an integer between 1 and 3 must divide evenly into
3.  The only such integer is 2.  Hence 2*2=3, and
3=4, as previously discussed.  But if 3=4, then
3+1=4+1 and 4=5.  Similarly 5=6.  By the same
argument, all integers after 5 are equal to 5.
Additionally, all rational numbers are equal to 1,
since 5/5=1.
The puzzle:  What numbers are left to number rules
by?  :)
Note:  5 is not a prime, because it is equal to 67
which is not a prime.

	VERDICT: Rule 15:i is judged INVALID

	SCORE: 2


FANTASY RULE 15:e  (Ronald)
Their are no integers left to number my Rules.
But Oerjan and I are not quite fools!
N included in Z included in Q included in R included in C:
there is an infinite set of numbers still left for me.

All future Rules shall only be validated by Stein,
when the poster has obeyed this law of mine:
Thou shalt not use any more,
any of the ten digits we have used before!

Oerjan requires that I symbolically spell it:
                       _
[0,1,2,3,4,5,6,7,8,9] ( ) Rule = empty   ==> Rule = VALID.

Dear players, no tell me:
how would you *describe* the tangens of pi?

	VERDICT: Rule 15:e is judged INVALID

	SCORE: 1


ROSE's LEMMA:
ALL irrationals are equal to e (or infinity)!
Any irrational can be expressed as a non-repeating decimal,
say for example 0.abcdefg.....  But that number is just
equivalent to a/10 + b/100 + c/1000 + ...  Each term is
rational, and so is equal to 1.  So the number as a whole
is 1+1+1+1+1... = infinity

-- Stein       stein.kulseth@tf.tele.no
               G=Stein;S=Kulseth;O=TF;P=tele;A=telemax;C=no;